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13400649718400 = 2752719292274783
BaseRepresentation
bin1100001100000001010011…
…1101110101101010000000
31202110002102022122000100202
43003000110331311222000
53224024012311442100
644300101250304332
72552110410124220
oct303002475655200
952402368560322
1013400649718400
1142a720245914a
1216051765880a8
137628a2aac4c9
143448485d4080
151838ad11e7d5
hexc3014f75a80

13400649718400 has 768 divisors, whose sum is σ = 41387493888000. Its totient is φ = 4183210967040.

The previous prime is 13400649718367. The next prime is 13400649718447. The reversal of 13400649718400 is 481794600431.

It is a super-3 number, since 3×134006497184003 (a number of 40 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2801722409 + ... + 2801727191.

It is an arithmetic number, because the mean of its divisors is an integer number (53889966000).

Almost surely, 213400649718400 is an apocalyptic number.

13400649718400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13400649718400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20693746944000).

13400649718400 is an abundant number, since it is smaller than the sum of its proper divisors (27986844169600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13400649718400 is a wasteful number, since it uses less digits than its factorization.

13400649718400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5089 (or 5072 counting only the distinct ones).

The product of its (nonzero) digits is 580608, while the sum is 47.

The spelling of 13400649718400 in words is "thirteen trillion, four hundred billion, six hundred forty-nine million, seven hundred eighteen thousand, four hundred".