1340101433133 has 24 divisors (see below), whose sum is σ = 1970967539736. Its totient is φ = 877177180800.

The previous prime is 1340101433129. The next prime is 1340101433179. The reversal of 1340101433133 is 3313341010431.

1340101433133 is a `hidden beast` number, since 1 + 340 + 1 + 0 + 1 + 4 + 3 + 313 + 3 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 66810359529 + 1273291073604 = 258477^2 + 1128402^2 .

It is not a de Polignac number, because 1340101433133 - 2² = 1340101433129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340101433097 and 1340101433106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340101433533) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1885398 + ... + 2496983.

It is an arithmetic number, because the mean of its divisors is an integer number (82123647489).

Almost surely, 2^{1340101433133} is an apocalyptic number.

It is an amenable number.

1340101433133 is a deficient number, since it is larger than the sum of its proper divisors (630866106603).

1340101433133 is a wasteful number, since it uses less digits than its factorization.

1340101433133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4383005 (or 4383002 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 1340101433133 its reverse (3313341010431), we get a palindrome (4653442443564).

The spelling of 1340101433133 in words is "one trillion, three hundred forty billion, one hundred one million, four hundred thirty-three thousand, one hundred thirty-three".