13401041330041 has 4 divisors (see below), whose sum is σ = 14106359294800. Its totient is φ = 12695723365284.

The previous prime is 13401041329993. The next prime is 13401041330087. The reversal of 13401041330041 is 14003314010431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401041330041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13401041329988 and 13401041330015.

It is not an unprimeable number, because it can be changed into a prime (13401041330741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352658982351 + ... + 352658982388.

It is an arithmetic number, because the mean of its divisors is an integer number (3526589823700).

Almost surely, 2^{13401041330041} is an apocalyptic number.

It is an amenable number.

13401041330041 is a deficient number, since it is larger than the sum of its proper divisors (705317964759).

13401041330041 is an equidigital number, since it uses as much as digits as its factorization.

13401041330041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 705317964758.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13401041330041 its reverse (14003314010431), we get a palindrome (27404355340472).

The spelling of 13401041330041 in words is "thirteen trillion, four hundred one billion, forty-one million, three hundred thirty thousand, forty-one".