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1340104330 = 25134010433
BaseRepresentation
bin100111111100000…
…0101111010001010
310110101122100112201
41033320011322022
510221031314310
6340551030414
745131461465
oct11770057212
93411570481
101340104330
116284aa244
1231496b40a
1318483a156
14c9da02dc
157c9b2e3a
hex4fe05e8a

1340104330 has 8 divisors (see below), whose sum is σ = 2412187812. Its totient is φ = 536041728.

The previous prime is 1340104327. The next prime is 1340104349. The reversal of 1340104330 is 334010431.

It can be written as a sum of positive squares in 2 ways, for example, as 1323286129 + 16818201 = 36377^2 + 4101^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1340104298 and 1340104307.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67005207 + ... + 67005226.

Almost surely, 21340104330 is an apocalyptic number.

1340104330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1340104330 is a deficient number, since it is larger than the sum of its proper divisors (1072083482).

1340104330 is a wasteful number, since it uses less digits than its factorization.

1340104330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134010440.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 1340104330 is about 36607.4354469143. The cubic root of 1340104330 is about 1102.5023829183.

Adding to 1340104330 its reverse (334010431), we get a palindrome (1674114761).

The spelling of 1340104330 in words is "one billion, three hundred forty million, one hundred four thousand, three hundred thirty".

Divisors: 1 2 5 10 134010433 268020866 670052165 1340104330