1340110111 has 8 divisors (see below), whose sum is σ = 1398970080. Its totient is φ = 1281299712.

The previous prime is 1340110103. The next prime is 1340110127. The reversal of 1340110111 is 1110110431.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340110111 - 2³ = 1340110103 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340110091 and 1340110100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340110151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49495 + ... + 71623.

It is an arithmetic number, because the mean of its divisors is an integer number (174871260).

Almost surely, 2^1340110111 is an apocalyptic number.

1340110111 is a deficient number, since it is larger than the sum of its proper divisors (58859969).

1340110111 is a wasteful number, since it uses less digits than its factorization.

1340110111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24785.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 1340110111 is about 36607.5144061981. The cubic root of 1340110111 is about 1102.5039682568.

Adding to 1340110111 its reverse (1110110431), we get a palindrome (2450220542).

The spelling of 1340110111 in words is "one billion, three hundred forty million, one hundred ten thousand, one hundred eleven".