13401101114125 has 8 divisors (see below), whose sum is σ = 16724574190584. Its totient is φ = 10720880891200.

The previous prime is 13401101114087. The next prime is 13401101114161. The reversal of 13401101114125 is 52141110110431.

It can be written as a sum of positive squares in 4 ways, for example, as 720194941449 + 12680906172676 = 848643^2 + 3561026^2 .

It is a de Polignac number, because none of the positive numbers 2^k-13401101114125 is a prime.

It is a super-2 number, since 2×13401101114125² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13401101114125.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 53604404332 + ... + 53604404581.

It is an arithmetic number, because the mean of its divisors is an integer number (2090571773823).

Almost surely, 2^{13401101114125} is an apocalyptic number.

It is an amenable number.

13401101114125 is a deficient number, since it is larger than the sum of its proper divisors (3323473076459).

13401101114125 is an equidigital number, since it uses as much as digits as its factorization.

13401101114125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107208808928 (or 107208808918 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 25.

Adding to 13401101114125 its reverse (52141110110431), we get a palindrome (65542211224556).

The spelling of 13401101114125 in words is "thirteen trillion, four hundred one billion, one hundred one million, one hundred fourteen thousand, one hundred twenty-five".