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13401115304134 = 26700557652067
BaseRepresentation
bin1100001100000011000010…
…1101111010000011000110
31202110010121202201012220211
43003000300231322003012
53224030441004213014
644300215401350034
72552125062416065
oct303006055720306
952403552635824
1013401115304134
1142a742124a648
12160528649831a
137629483a531c
1434489038c1dc
151838d8e3acc4
hexc3030b7a0c6

13401115304134 has 4 divisors (see below), whose sum is σ = 20101672956204. Its totient is φ = 6700557652066.

The previous prime is 13401115304117. The next prime is 13401115304173. The reversal of 13401115304134 is 43140351110431.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×134011153041342 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13401115304096 and 13401115304105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350278826032 + ... + 3350278826035.

It is an arithmetic number, because the mean of its divisors is an integer number (5025418239051).

Almost surely, 213401115304134 is an apocalyptic number.

13401115304134 is a deficient number, since it is larger than the sum of its proper divisors (6700557652070).

13401115304134 is an equidigital number, since it uses as much as digits as its factorization.

13401115304134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6700557652069.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 13401115304134 its reverse (43140351110431), we get a palindrome (56541466414565).

The spelling of 13401115304134 in words is "thirteen trillion, four hundred one billion, one hundred fifteen million, three hundred four thousand, one hundred thirty-four".

Divisors: 1 2 6700557652067 13401115304134