Base | Representation |
---|---|
bin | 10011100000000100111… |
… | …010001010101001110001 |
3 | 11202010001201102221222220 |
4 | 103200010322022221301 |
5 | 133424022202400301 |
6 | 2503350010151253 |
7 | 165551141232423 |
oct | 23400472125161 |
9 | 4663051387886 |
10 | 1340112153201 |
11 | 47737a412628 |
12 | 197880a22529 |
13 | 994ab487133 |
14 | 48c0c9cc813 |
15 | 24cd56b2936 |
hex | 13804e8aa71 |
1340112153201 has 8 divisors (see below), whose sum is σ = 1786842767904. Its totient is φ = 893394820320.
The previous prime is 1340112153167. The next prime is 1340112153223. The reversal of 1340112153201 is 1023512110431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1340112153201 - 26 = 1340112153137 is a prime.
It is a super-4 number, since 4×13401121532014 (a number of 50 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (1340112153241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3082591 + ... + 3490356.
It is an arithmetic number, because the mean of its divisors is an integer number (223355345988).
Almost surely, 21340112153201 is an apocalyptic number.
It is an amenable number.
1340112153201 is a deficient number, since it is larger than the sum of its proper divisors (446730614703).
1340112153201 is an equidigital number, since it uses as much as digits as its factorization.
1340112153201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6640911.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 1340112153201 its reverse (1023512110431), we get a palindrome (2363624263632).
The spelling of 1340112153201 in words is "one trillion, three hundred forty billion, one hundred twelve million, one hundred fifty-three thousand, two hundred one".
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