Base | Representation |
---|---|
bin | 10011100000000100111… |
… | …010001010101001110000 |
3 | 11202010001201102221222212 |
4 | 103200010322022221300 |
5 | 133424022202400300 |
6 | 2503350010151252 |
7 | 165551141232422 |
oct | 23400472125160 |
9 | 4663051387885 |
10 | 1340112153200 |
11 | 47737a412627 |
12 | 197880a22528 |
13 | 994ab487132 |
14 | 48c0c9cc812 |
15 | 24cd56b2935 |
hex | 13804e8aa70 |
1340112153200 has 60 divisors (see below), whose sum is σ = 3229346714088. Its totient is φ = 534425337600.
The previous prime is 1340112153167. The next prime is 1340112153223. The reversal of 1340112153200 is 23512110431.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4928447 + ... + 5193246.
Almost surely, 21340112153200 is an apocalyptic number.
1340112153200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1340112153200 is an abundant number, since it is smaller than the sum of its proper divisors (1889234560888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1340112153200 is a wasteful number, since it uses less digits than its factorization.
1340112153200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10122042 (or 10122031 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 1340112153200 its reverse (23512110431), we get a palindrome (1363624263631).
The spelling of 1340112153200 in words is "one trillion, three hundred forty billion, one hundred twelve million, one hundred fifty-three thousand, two hundred".
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