Base | Representation |
---|---|
bin | 1100001100000011011010… |
… | …0110111100101110110100 |
3 | 1202110010212122200202220211 |
4 | 3003000312212330232310 |
5 | 3224031141310042122 |
6 | 44300233252035204 |
7 | 2552130402505204 |
oct | 303006646745664 |
9 | 52403778622824 |
10 | 13401214143412 |
11 | 42a7472018aa7 |
12 | 16052b3602b04 |
13 | 762962a006c4 |
14 | 34489d55a404 |
15 | 1838e2961877 |
hex | c30369bcbb4 |
13401214143412 has 12 divisors (see below), whose sum is σ = 23452876808676. Its totient is φ = 6700392198080.
The previous prime is 13401214143397. The next prime is 13401214143521. The reversal of 13401214143412 is 21434141210431.
13401214143412 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 5217003173776 + 8184210969636 = 2284076^2 + 2860806^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53578039 + ... + 53827582.
It is an arithmetic number, because the mean of its divisors is an integer number (1954406400723).
Almost surely, 213401214143412 is an apocalyptic number.
It is an amenable number.
13401214143412 is a deficient number, since it is larger than the sum of its proper divisors (10051662665264).
13401214143412 is a wasteful number, since it uses less digits than its factorization.
13401214143412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107436818 (or 107436816 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 13401214143412 its reverse (21434141210431), we get a palindrome (34835355353843).
The spelling of 13401214143412 in words is "thirteen trillion, four hundred one billion, two hundred fourteen million, one hundred forty-three thousand, four hundred twelve".
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