Base | Representation |
---|---|
bin | 11110011110001000100011… |
… | …011000100111001111010101 |
3 | 122120111102211001221211000111 |
4 | 132132020203120213033111 |
5 | 120031123402241141113 |
6 | 1153004200552043021 |
7 | 40141026222340606 |
oct | 3636104330471725 |
9 | 576442731854014 |
10 | 134012163224533 |
11 | 3977826a4a5480 |
12 | 13044556393471 |
13 | 59a13a62947a9 |
14 | 251431aa87dad |
15 | 1075e6d2b713d |
hex | 79e2236273d5 |
134012163224533 has 64 divisors (see below), whose sum is σ = 159079923302400. Its totient is φ = 111622674240000.
The previous prime is 134012163224519. The next prime is 134012163224557. The reversal of 134012163224533 is 335422361210431.
It is not a de Polignac number, because 134012163224533 - 29 = 134012163224021 is a prime.
It is a super-3 number, since 3×1340121632245333 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134012163224573) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2795448678 + ... + 2795496616.
It is an arithmetic number, because the mean of its divisors is an integer number (2485623801600).
Almost surely, 2134012163224533 is an apocalyptic number.
It is an amenable number.
134012163224533 is a deficient number, since it is larger than the sum of its proper divisors (25067760077867).
134012163224533 is a wasteful number, since it uses less digits than its factorization.
134012163224533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51634.
The product of its (nonzero) digits is 311040, while the sum is 40.
The spelling of 134012163224533 in words is "one hundred thirty-four trillion, twelve billion, one hundred sixty-three million, two hundred twenty-four thousand, five hundred thirty-three".
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