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1340122004301 = 34338472700427
BaseRepresentation
bin10011100000000101011…
…111101111101101001101
311202010002101222110011110
4103200011133233231031
5133424032213114201
62503351001242233
7165551321042013
oct23400537575515
94663071873143
101340122004301
11477384a30933
12197884193379
13994b0525ca2
1448c100348b3
1524cd64ab6d6
hex138057efb4d

1340122004301 has 16 divisors (see below), whose sum is σ = 1828859462144. Its totient is φ = 872410425264.

The previous prime is 1340122004281. The next prime is 1340122004383. The reversal of 1340122004301 is 1034002210431.

It is not a de Polignac number, because 1340122004301 - 27 = 1340122004173 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340122004101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 853951 + ... + 1846476.

It is an arithmetic number, because the mean of its divisors is an integer number (114303716384).

Almost surely, 21340122004301 is an apocalyptic number.

It is an amenable number.

1340122004301 is a deficient number, since it is larger than the sum of its proper divisors (488737457843).

1340122004301 is a wasteful number, since it uses less digits than its factorization.

1340122004301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2704320.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1340122004301 its reverse (1034002210431), we get a palindrome (2374124214732).

The spelling of 1340122004301 in words is "one trillion, three hundred forty billion, one hundred twenty-two million, four thousand, three hundred one".

Divisors: 1 3 43 129 3847 11541 165421 496263 2700427 8101281 116118361 348355083 10388542669 31165628007 446707334767 1340122004301