Base | Representation |
---|---|
bin | 1100001100000011011100… |
… | …0001001100010110111011 |
3 | 1202110010220010122022011102 |
4 | 3003000313001030112323 |
5 | 3224031200040220123 |
6 | 44300234055322015 |
7 | 2552130515130611 |
oct | 303006701142673 |
9 | 52403803568142 |
10 | 13401221023163 |
11 | 42a7475997946 |
12 | 16052b598030b |
13 | 76296426bc6c |
14 | 3448a042b6b1 |
15 | 1838e3370028 |
hex | c303704c5bb |
13401221023163 has 2 divisors, whose sum is σ = 13401221023164. Its totient is φ = 13401221023162.
The previous prime is 13401221023139. The next prime is 13401221023189. The reversal of 13401221023163 is 36132012210431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13401221023163 - 28 = 13401221022907 is a prime.
It is not a weakly prime, because it can be changed into another prime (13401221023763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700610511581 + 6700610511582.
It is an arithmetic number, because the mean of its divisors is an integer number (6700610511582).
Almost surely, 213401221023163 is an apocalyptic number.
13401221023163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401221023163 is an equidigital number, since it uses as much as digits as its factorization.
13401221023163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13401221023163 its reverse (36132012210431), we get a palindrome (49533233233594).
The spelling of 13401221023163 in words is "thirteen trillion, four hundred one billion, two hundred twenty-one million, twenty-three thousand, one hundred sixty-three".
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