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13401221222 = 26700610611
BaseRepresentation
bin11000111101100011…
…00110100001100110
31021120221202120111202
430132301212201212
5204421203034342
610053442402502
7653044333544
oct143661464146
937527676452
1013401221222
115757704944
122720060432
1313575500cc
14911b6ad94
155367a7332
hex31ec66866

13401221222 has 4 divisors (see below), whose sum is σ = 20101831836. Its totient is φ = 6700610610.

The previous prime is 13401221177. The next prime is 13401221279. The reversal of 13401221222 is 22212210431.

13401221222 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13401221194 and 13401221203.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350305304 + ... + 3350305307.

It is an arithmetic number, because the mean of its divisors is an integer number (5025457959).

Almost surely, 213401221222 is an apocalyptic number.

13401221222 is a deficient number, since it is larger than the sum of its proper divisors (6700610614).

13401221222 is an equidigital number, since it uses as much as digits as its factorization.

13401221222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6700610613.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 13401221222 its reverse (22212210431), we get a palindrome (35613431653).

The spelling of 13401221222 in words is "thirteen billion, four hundred one million, two hundred twenty-one thousand, two hundred twenty-two".

Divisors: 1 2 6700610611 13401221222