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13401223 = 1110911177
BaseRepresentation
bin110011000111…
…110010000111
3221012212000121
4303013302013
511412314343
61155122411
7221623423
oct63076207
927185017
1013401223
1176235a0
1245a3407
132a12a24
141acbb83
15129aaed
hexcc7c87

13401223 has 8 divisors (see below), whose sum is σ = 14754960. Its totient is φ = 12070080.

The previous prime is 13401217. The next prime is 13401233. The reversal of 13401223 is 32210431.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13401223 - 25 = 13401191 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13401197 and 13401206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13401233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4390 + ... + 6787.

It is an arithmetic number, because the mean of its divisors is an integer number (1844370).

Almost surely, 213401223 is an apocalyptic number.

13401223 is a deficient number, since it is larger than the sum of its proper divisors (1353737).

13401223 is a wasteful number, since it uses less digits than its factorization.

13401223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11297.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 13401223 is about 3660.7680888032. The cubic root of 13401223 is about 237.5279996537.

Adding to 13401223 its reverse (32210431), we get a palindrome (45611654).

The spelling of 13401223 in words is "thirteen million, four hundred one thousand, two hundred twenty-three".

Divisors: 1 11 109 1199 11177 122947 1218293 13401223