1340125211 has 2 divisors, whose sum is σ = 1340125212. Its totient is φ = 1340125210.

The previous prime is 1340125183. The next prime is 1340125253. The reversal of 1340125211 is 1125210431.

It is a weak prime.

It is an emirp because it is prime and its reverse (1125210431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340125211 is a prime.

It is not a weakly prime, because it can be changed into another prime (1340125411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670062605 + 670062606.

It is an arithmetic number, because the mean of its divisors is an integer number (670062606).

Almost surely, 2^1340125211 is an apocalyptic number.

1340125211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340125211 is an equidigital number, since it uses as much as digits as its factorization.

1340125211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 1340125211 is about 36607.7206474263. The cubic root of 1340125211 is about 1102.5081091473.

Adding to 1340125211 its reverse (1125210431), we get a palindrome (2465335642).

The spelling of 1340125211 in words is "one billion, three hundred forty million, one hundred twenty-five thousand, two hundred eleven".