Base | Representation |
---|---|
bin | 10011100000000101110… |
… | …001001010111101100011 |
3 | 11202010002201120112101211 |
4 | 103200011301022331203 |
5 | 133424034400304022 |
6 | 2503351243210551 |
7 | 165551404626031 |
oct | 23400561127543 |
9 | 4663081515354 |
10 | 1340126572387 |
11 | 477387570a09 |
12 | 197885816a57 |
13 | 994b14652b5 |
14 | 48c108a3551 |
15 | 24cd6aaee77 |
hex | 13805c4af63 |
1340126572387 has 2 divisors, whose sum is σ = 1340126572388. Its totient is φ = 1340126572386.
The previous prime is 1340126572349. The next prime is 1340126572429. The reversal of 1340126572387 is 7832756210431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340126572387 - 211 = 1340126570339 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1340126572387.
It is not a weakly prime, because it can be changed into another prime (1340126572487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670063286193 + 670063286194.
It is an arithmetic number, because the mean of its divisors is an integer number (670063286194).
Almost surely, 21340126572387 is an apocalyptic number.
1340126572387 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340126572387 is an equidigital number, since it uses as much as digits as its factorization.
1340126572387 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1693440, while the sum is 49.
The spelling of 1340126572387 in words is "one trillion, three hundred forty billion, one hundred twenty-six million, five hundred seventy-two thousand, three hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •