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134013032431 = 521257222711
BaseRepresentation
bin111110011001111001…
…1001001011111101111
3110210220121011102012121
41330303303021133233
54143424314014211
6141321552213411
712452652660235
oct1746363113757
9423817142177
10134013032431
115191a954863
1221b8083a267
13c83940a135
1466b4452955
153745310271
hex1f33cc97ef

134013032431 has 4 divisors (see below), whose sum is σ = 134270255664. Its totient is φ = 133755809200.

The previous prime is 134013032347. The next prime is 134013032437. The reversal of 134013032431 is 134230310431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134013032431 - 213 = 134013024239 is a prime.

It is a super-2 number, since 2×1340130324312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134013032396 and 134013032405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134013032437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128610835 + ... + 128611876.

It is an arithmetic number, because the mean of its divisors is an integer number (33567563916).

Almost surely, 2134013032431 is an apocalyptic number.

134013032431 is a deficient number, since it is larger than the sum of its proper divisors (257223233).

134013032431 is an equidigital number, since it uses as much as digits as its factorization.

134013032431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 257223232.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 134013032431 its reverse (134230310431), we get a palindrome (268243342862).

The spelling of 134013032431 in words is "one hundred thirty-four billion, thirteen million, thirty-two thousand, four hundred thirty-one".

Divisors: 1 521 257222711 134013032431