Base | Representation |
---|---|
bin | 11110011110001001010111… |
… | …101001010101001110101011 |
3 | 122120111112002011210202122011 |
4 | 132132021113221111032223 |
5 | 120031132201221204233 |
6 | 1153004423552540351 |
7 | 40141060030113001 |
oct | 3636112751251653 |
9 | 576445064722564 |
10 | 134013040022443 |
11 | 3977867a41a74a |
12 | 1304475bb516b7 |
13 | 59a14b5b2641a |
14 | 25143a12c4a71 |
15 | 1075ec025e0cd |
hex | 79e257a553ab |
134013040022443 has 2 divisors, whose sum is σ = 134013040022444. Its totient is φ = 134013040022442.
The previous prime is 134013040022419. The next prime is 134013040022507. The reversal of 134013040022443 is 344220040310431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134013040022443 - 213 = 134013040014251 is a prime.
It is not a weakly prime, because it can be changed into another prime (134013040022843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006520011221 + 67006520011222.
It is an arithmetic number, because the mean of its divisors is an integer number (67006520011222).
Almost surely, 2134013040022443 is an apocalyptic number.
134013040022443 is a deficient number, since it is larger than the sum of its proper divisors (1).
134013040022443 is an equidigital number, since it uses as much as digits as its factorization.
134013040022443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 134013040022443 its reverse (344220040310431), we get a palindrome (478233080332874).
The spelling of 134013040022443 in words is "one hundred thirty-four trillion, thirteen billion, forty million, twenty-two thousand, four hundred forty-three".
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