Base | Representation |
---|---|
bin | 11110011110001001011100… |
… | …011010110100110001001111 |
3 | 122120111112021202111102000012 |
4 | 132132021130122310301033 |
5 | 120031132332221334201 |
6 | 1153004435533223435 |
7 | 40141062021603311 |
oct | 3636113432646117 |
9 | 576445252442005 |
10 | 134013120105551 |
11 | 39778710648335 |
12 | 13044782931b7b |
13 | 59a14c95b558b |
14 | 25143abbad7b1 |
15 | 1075ec72cc5bb |
hex | 79e25c6b4c4f |
134013120105551 has 4 divisors (see below), whose sum is σ = 135900628839504. Its totient is φ = 132125611371600.
The previous prime is 134013120105511. The next prime is 134013120105559. The reversal of 134013120105551 is 155501021310431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134013120105551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134013120105559) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 943754366870 + ... + 943754367011.
It is an arithmetic number, because the mean of its divisors is an integer number (33975157209876).
Almost surely, 2134013120105551 is an apocalyptic number.
134013120105551 is a deficient number, since it is larger than the sum of its proper divisors (1887508733953).
134013120105551 is an equidigital number, since it uses as much as digits as its factorization.
134013120105551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1887508733952.
The product of its (nonzero) digits is 9000, while the sum is 32.
Adding to 134013120105551 its reverse (155501021310431), we get a palindrome (289514141415982).
The spelling of 134013120105551 in words is "one hundred thirty-four trillion, thirteen billion, one hundred twenty million, one hundred five thousand, five hundred fifty-one".
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