1340131405121 has 2 divisors, whose sum is σ = 1340131405122. Its totient is φ = 1340131405120.

The previous prime is 1340131405061. The next prime is 1340131405201. The reversal of 1340131405121 is 1215041310431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1320053932096 + 20077473025 = 1148936^2 + 141695^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340131405121 - 2³⁴ = 1322951535937 is a prime.

It is a super-3 number, since 3×1340131405121³ (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1340131405621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670065702560 + 670065702561.

It is an arithmetic number, because the mean of its divisors is an integer number (670065702561).

Almost surely, 2^{1340131405121} is an apocalyptic number.

It is an amenable number.

1340131405121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340131405121 is an equidigital number, since it uses as much as digits as its factorization.

1340131405121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 1340131405121 its reverse (1215041310431), we get a palindrome (2555172715552).

The spelling of 1340131405121 in words is "one trillion, three hundred forty billion, one hundred thirty-one million, four hundred five thousand, one hundred twenty-one".