Base | Representation |
---|---|
bin | 11110011110001010011000… |
… | …011100000100000000000000 |
3 | 122120111121212221021011000000 |
4 | 132132022120130010000000 |
5 | 120031141413012004130 |
6 | 1153005123504000000 |
7 | 40141125666602400 |
oct | 3636123034040000 |
9 | 576447787234000 |
10 | 134014127063040 |
11 | 39779087a93404 |
12 | 13044a04000000 |
13 | 59a162a0ba503 |
14 | 251446580c800 |
15 | 10760358d5260 |
hex | 79e298704000 |
134014127063040 has 2520 divisors, whose sum is σ = 575140622441112. Its totient is φ = 29857928970240.
The previous prime is 134014127063023. The next prime is 134014127063057. The reversal of 134014127063040 is 40360721410431.
134014127063040 is a `hidden beast` number, since 1 + 3 + 4 + 0 + 1 + 4 + 12 + 7 + 0 + 630 + 4 + 0 = 666.
It is an interprime number because it is at equal distance from previous prime (134014127063023) and next prime (134014127063057).
It can be written as a sum of positive squares in 4 ways, for example, as 8011526455296 + 126002600607744 = 2830464^2 + 11225088^2 .
It is a tau number, because it is divible by the number of its divisors (2520).
It is a super-2 number, since 2×1340141270630402 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a junction number, because it is equal to n+sod(n) for n = 134014127062986 and 134014127063004.
It is an unprimeable number.
It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 119976836562 + ... + 119976837678.
Almost surely, 2134014127063040 is an apocalyptic number.
134014127063040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 134014127063040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (287570311220556).
134014127063040 is an abundant number, since it is smaller than the sum of its proper divisors (441126495378072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134014127063040 is an frugal number, since it uses more digits than its factorization.
134014127063040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1223 (or 1175 counting only the distinct ones).
The product of its (nonzero) digits is 48384, while the sum is 36.
Adding to 134014127063040 its reverse (40360721410431), we get a palindrome (174374848473471).
The spelling of 134014127063040 in words is "one hundred thirty-four trillion, fourteen billion, one hundred twenty-seven million, sixty-three thousand, forty".
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