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1340141433041 is a prime number
BaseRepresentation
bin10011100000000110101…
…001110111000011010001
311202010010202112112101102
4103200012221313003101
5133424102201324131
62503352533514145
7165551645141405
oct23400651670321
94663122475342
101340141433041
114773949a0a44
1219788a7a2955
13994b4569398
1448c12851105
1524cd80481cb
hex13806a770d1

1340141433041 has 2 divisors, whose sum is σ = 1340141433042. Its totient is φ = 1340141433040.

The previous prime is 1340141433019. The next prime is 1340141433053. The reversal of 1340141433041 is 1403341410431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 748780433041 + 591361000000 = 865321^2 + 769000^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340141433041 - 26 = 1340141432977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340141432995 and 1340141433013.

It is not a weakly prime, because it can be changed into another prime (1340141433061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670070716520 + 670070716521.

It is an arithmetic number, because the mean of its divisors is an integer number (670070716521).

Almost surely, 21340141433041 is an apocalyptic number.

It is an amenable number.

1340141433041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340141433041 is an equidigital number, since it uses as much as digits as its factorization.

1340141433041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1340141433041 its reverse (1403341410431), we get a palindrome (2743482843472).

The spelling of 1340141433041 in words is "one trillion, three hundred forty billion, one hundred forty-one million, four hundred thirty-three thousand, forty-one".