Base | Representation |
---|---|
bin | 1100001100000100001011… |
… | …1100110011111101011100 |
3 | 1202110011102002022101212102 |
4 | 3003001002330303331130 |
5 | 3224032102311414434 |
6 | 44300310010024232 |
7 | 2552135465456306 |
oct | 303010274637534 |
9 | 52404362271772 |
10 | 13401421201244 |
11 | 42a756899167a |
12 | 1605350a18078 |
13 | 76299688932b |
14 | 3448bcc58976 |
15 | 183905c1207e |
hex | c3042f33f5c |
13401421201244 has 6 divisors (see below), whose sum is σ = 23452487102184. Its totient is φ = 6700710600620.
The previous prime is 13401421201243. The next prime is 13401421201271. The reversal of 13401421201244 is 44210212410431.
13401421201244 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13401421201243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1675177650152 + ... + 1675177650159.
It is an arithmetic number, because the mean of its divisors is an integer number (3908747850364).
Almost surely, 213401421201244 is an apocalyptic number.
It is an amenable number.
13401421201244 is a deficient number, since it is larger than the sum of its proper divisors (10051065900940).
13401421201244 is a wasteful number, since it uses less digits than its factorization.
13401421201244 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3350355300315 (or 3350355300313 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 13401421201244 its reverse (44210212410431), we get a palindrome (57611633611675).
The spelling of 13401421201244 in words is "thirteen trillion, four hundred one billion, four hundred twenty-one million, two hundred one thousand, two hundred forty-four".
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