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134014313 is a prime number
BaseRepresentation
bin1111111110011…
…10010101101001
3100100011122002002
413333032111221
5233301424223
621144220345
73215050166
oct777162551
9310148062
10134014313
1169713a34
1238a6a6b5
13219c2a14
1413b2706d
15bb72e28
hex7fce569

134014313 has 2 divisors, whose sum is σ = 134014314. Its totient is φ = 134014312.

The previous prime is 134014291. The next prime is 134014339. The reversal of 134014313 is 313410431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131859289 + 2155024 = 11483^2 + 1468^2 .

It is an emirp because it is prime and its reverse (313410431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134014313 is a prime.

It is not a weakly prime, because it can be changed into another prime (134014513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67007156 + 67007157.

It is an arithmetic number, because the mean of its divisors is an integer number (67007157).

Almost surely, 2134014313 is an apocalyptic number.

It is an amenable number.

134014313 is a deficient number, since it is larger than the sum of its proper divisors (1).

134014313 is an equidigital number, since it uses as much as digits as its factorization.

134014313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 134014313 is about 11576.4551137211. The cubic root of 134014313 is about 511.7412136725.

Adding to 134014313 its reverse (313410431), we get a palindrome (447424744).

The spelling of 134014313 in words is "one hundred thirty-four million, fourteen thousand, three hundred thirteen".