1340144011 has 2 divisors, whose sum is σ = 1340144012. Its totient is φ = 1340144010.

The previous prime is 1340143997. The next prime is 1340144023. The reversal of 1340144011 is 1104410431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340144011 - 2⁹ = 1340143499 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1340144011.

It is not a weakly prime, because it can be changed into another prime (1340184011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670072005 + 670072006.

It is an arithmetic number, because the mean of its divisors is an integer number (670072006).

Almost surely, 2^1340144011 is an apocalyptic number.

1340144011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340144011 is an equidigital number, since it uses as much as digits as its factorization.

1340144011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 1340144011 is about 36607.9774229607. The cubic root of 1340144011 is about 1102.5132646495.

Adding to 1340144011 its reverse (1104410431), we get a palindrome (2444554442).

The spelling of 1340144011 in words is "one billion, three hundred forty million, one hundred forty-four thousand, eleven".