Base | Representation |
---|---|
bin | 11110011110001010101001… |
… | …100111101100100100000011 |
3 | 122120111122122000200101200022 |
4 | 132132022221213230210003 |
5 | 120031143010310403233 |
6 | 1153005212242244055 |
7 | 40141136100024512 |
oct | 3636125147544403 |
9 | 576448560611608 |
10 | 134014415325443 |
11 | 397792157801a4 |
12 | 13044a8465662b |
13 | 59a1674a38893 |
14 | 2514491c08679 |
15 | 1076050d76398 |
hex | 79e2a99ec903 |
134014415325443 has 2 divisors, whose sum is σ = 134014415325444. Its totient is φ = 134014415325442.
The previous prime is 134014415325421. The next prime is 134014415325451. The reversal of 134014415325443 is 344523514410431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134014415325443 - 224 = 134014398548227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134014415325394 and 134014415325403.
It is not a weakly prime, because it can be changed into another prime (134014415325463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67007207662721 + 67007207662722.
It is an arithmetic number, because the mean of its divisors is an integer number (67007207662722).
Almost surely, 2134014415325443 is an apocalyptic number.
134014415325443 is a deficient number, since it is larger than the sum of its proper divisors (1).
134014415325443 is an equidigital number, since it uses as much as digits as its factorization.
134014415325443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1382400, while the sum is 44.
Adding to 134014415325443 its reverse (344523514410431), we get a palindrome (478537929735874).
The spelling of 134014415325443 in words is "one hundred thirty-four trillion, fourteen billion, four hundred fifteen million, three hundred twenty-five thousand, four hundred forty-three".
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