Base | Representation |
---|---|
bin | 10011100000000110111… |
… | …000000011010101100001 |
3 | 11202010011000112112201122 |
4 | 103200012320003111201 |
5 | 133424104124402002 |
6 | 2503353145342025 |
7 | 165552021565022 |
oct | 23400670032541 |
9 | 4663130475648 |
10 | 1340145153377 |
11 | 4773970020a8 |
12 | 19788ba97915 |
13 | 994b526c874 |
14 | 48c1313cc49 |
15 | 24cd85306a2 |
hex | 13806e03561 |
1340145153377 has 2 divisors, whose sum is σ = 1340145153378. Its totient is φ = 1340145153376.
The previous prime is 1340145153343. The next prime is 1340145153407. The reversal of 1340145153377 is 7733515410431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1161736909921 + 178408243456 = 1077839^2 + 422384^2 .
It is a cyclic number.
It is not a de Polignac number, because 1340145153377 - 28 = 1340145153121 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340145153077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670072576688 + 670072576689.
It is an arithmetic number, because the mean of its divisors is an integer number (670072576689).
Almost surely, 21340145153377 is an apocalyptic number.
It is an amenable number.
1340145153377 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340145153377 is an equidigital number, since it uses as much as digits as its factorization.
1340145153377 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 529200, while the sum is 44.
The spelling of 1340145153377 in words is "one trillion, three hundred forty billion, one hundred forty-five million, one hundred fifty-three thousand, three hundred seventy-seven".
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