1340154131 has 4 divisors (see below), whose sum is σ = 1365440112. Its totient is φ = 1314868152.

The previous prime is 1340154121. The next prime is 1340154169. The reversal of 1340154131 is 1314510431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340154131 - 2¹⁰ = 1340153107 is a prime.

It is a super-2 number, since 2×1340154131² = 3592026189672730322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340154097 and 1340154106.

It is not an unprimeable number, because it can be changed into a prime (1340154121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12642911 + ... + 12643016.

It is an arithmetic number, because the mean of its divisors is an integer number (341360028).

Almost surely, 2^1340154131 is an apocalyptic number.

1340154131 is a deficient number, since it is larger than the sum of its proper divisors (25285981).

1340154131 is an equidigital number, since it uses as much as digits as its factorization.

1340154131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25285980.

The product of its (nonzero) digits is 720, while the sum is 23.

The square root of 1340154131 is about 36608.1156439388. The cubic root of 1340154131 is about 1102.5160398254.

Adding to 1340154131 its reverse (1314510431), we get a palindrome (2654664562).

The spelling of 1340154131 in words is "one billion, three hundred forty million, one hundred fifty-four thousand, one hundred thirty-one".