Base | Representation |
---|---|
bin | 11000111101100110… |
… | …00101100011000001 |
3 | 1021120222111100101222 |
4 | 30132303011203001 |
5 | 204421303013213 |
6 | 10053455004425 |
7 | 653050544351 |
oct | 143663054301 |
9 | 37528440358 |
10 | 13401610433 |
11 | 5757950302 |
12 | 2720209715 |
13 | 1357658303 |
14 | 911c2cb61 |
15 | 536832808 |
hex | 31ecc58c1 |
13401610433 has 2 divisors, whose sum is σ = 13401610434. Its totient is φ = 13401610432.
The previous prime is 13401610421. The next prime is 13401610441. The reversal of 13401610433 is 33401610431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8435871409 + 4965739024 = 91847^2 + 70468^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13401610433 is a prime.
It is not a weakly prime, because it can be changed into another prime (13401610463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700805216 + 6700805217.
It is an arithmetic number, because the mean of its divisors is an integer number (6700805217).
Almost surely, 213401610433 is an apocalyptic number.
It is an amenable number.
13401610433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401610433 is an equidigital number, since it uses as much as digits as its factorization.
13401610433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 26.
The spelling of 13401610433 in words is "thirteen billion, four hundred one million, six hundred ten thousand, four hundred thirty-three".
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