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1340200102 = 2670100051
BaseRepresentation
bin100111111100001…
…1101010010100110
310110101211012220211
41033320131102212
510221042400402
6340553050034
745132340633
oct11770352246
93411735824
101340200102
1162856519a
123149b691a
13184871917
14c9dc718a
157c9d14d7
hex4fe1d4a6

1340200102 has 4 divisors (see below), whose sum is σ = 2010300156. Its totient is φ = 670100050.

The previous prime is 1340200097. The next prime is 1340200109. The reversal of 1340200102 is 2010020431.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×13402001022 = 3592272626801620808, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340200109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335050024 + ... + 335050027.

It is an arithmetic number, because the mean of its divisors is an integer number (502575039).

Almost surely, 21340200102 is an apocalyptic number.

1340200102 is a deficient number, since it is larger than the sum of its proper divisors (670100054).

1340200102 is an equidigital number, since it uses as much as digits as its factorization.

1340200102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 670100053.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 1340200102 is about 36608.7435184547. The cubic root of 1340200102 is about 1102.5286461329.

Adding to 1340200102 its reverse (2010020431), we get a palindrome (3350220533).

The spelling of 1340200102 in words is "one billion, three hundred forty million, two hundred thousand, one hundred two".

Divisors: 1 2 670100051 1340200102