13402001043000 has 640 divisors, whose sum is σ = 48559982328000. Its totient is φ = 3443716684800.

The previous prime is 13402001042999. The next prime is 13402001043007. The reversal of 13402001043000 is 34010020431.

13402001043000 is a `hidden beast` number, since 1 + 34 + 0 + 200 + 1 + 0 + 430 + 0 + 0 = 666.

It is a super-2 number, since 2×13402001043000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402001043007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 1228521546 + ... + 1228532454.

Almost surely, 2^{13402001043000} is an apocalyptic number.

13402001043000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13402001043000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24279991164000).

13402001043000 is an abundant number, since it is smaller than the sum of its proper divisors (35157981285000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13402001043000 is a wasteful number, since it uses less digits than its factorization.

13402001043000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11494 (or 11471 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 18.

Adding to 13402001043000 its reverse (34010020431), we get a palindrome (13436011063431).

The spelling of 13402001043000 in words is "thirteen trillion, four hundred two billion, one million, forty-three thousand".