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134020101121 is a prime number
BaseRepresentation
bin111110011010000111…
…0000111010000000001
3110210221002110112121221
41330310032013100001
54143433121213441
6141322403515041
712453100030534
oct1746416072001
9423832415557
10134020101121
1151923942655
1221b83088a81
13c83aa136aa
1466b5372a1b
153745c598d1
hex1f34387401

134020101121 has 2 divisors, whose sum is σ = 134020101122. Its totient is φ = 134020101120.

The previous prime is 134020101101. The next prime is 134020101167. The reversal of 134020101121 is 121101020431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126230273521 + 7789827600 = 355289^2 + 88260^2 .

It is a cyclic number.

It is not a de Polignac number, because 134020101121 - 29 = 134020100609 is a prime.

It is a super-2 number, since 2×1340201011212 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134020101095 and 134020101104.

It is not a weakly prime, because it can be changed into another prime (134020101101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010050560 + 67010050561.

It is an arithmetic number, because the mean of its divisors is an integer number (67010050561).

Almost surely, 2134020101121 is an apocalyptic number.

It is an amenable number.

134020101121 is a deficient number, since it is larger than the sum of its proper divisors (1).

134020101121 is an equidigital number, since it uses as much as digits as its factorization.

134020101121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 134020101121 its reverse (121101020431), we get a palindrome (255121121552).

The spelling of 134020101121 in words is "one hundred thirty-four billion, twenty million, one hundred one thousand, one hundred twenty-one".