Base | Representation |
---|---|
bin | 111110011010000111… |
… | …0000111010101001011 |
3 | 110210221002110120002011 |
4 | 1330310032013111023 |
5 | 4143433121221301 |
6 | 141322403520351 |
7 | 12453100031515 |
oct | 1746416072513 |
9 | 423832416064 |
10 | 134020101451 |
11 | 51923942925 |
12 | 21b830890b7 |
13 | c83aa138a2 |
14 | 66b5372bb5 |
15 | 3745c59a51 |
hex | 1f3438754b |
134020101451 has 2 divisors, whose sum is σ = 134020101452. Its totient is φ = 134020101450.
The previous prime is 134020101421. The next prime is 134020101463. The reversal of 134020101451 is 154101020431.
It is a strong prime.
It is an emirp because it is prime and its reverse (154101020431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134020101451 - 223 = 134011712843 is a prime.
It is a super-2 number, since 2×1340201014512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134020101421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010050725 + 67010050726.
It is an arithmetic number, because the mean of its divisors is an integer number (67010050726).
Almost surely, 2134020101451 is an apocalyptic number.
134020101451 is a deficient number, since it is larger than the sum of its proper divisors (1).
134020101451 is an equidigital number, since it uses as much as digits as its factorization.
134020101451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 134020101451 its reverse (154101020431), we get a palindrome (288121121882).
The spelling of 134020101451 in words is "one hundred thirty-four billion, twenty million, one hundred one thousand, four hundred fifty-one".
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