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134020101515 = 526804020303
BaseRepresentation
bin111110011010000111…
…0000111010110001011
3110210221002110120011112
41330310032013112023
54143433121222030
6141322403520535
712453100031636
oct1746416072613
9423832416145
10134020101515
1151923942983
1221b8308914b
13c83aa13921
1466b5372c1d
153745c59a95
hex1f3438758b

134020101515 has 4 divisors (see below), whose sum is σ = 160824121824. Its totient is φ = 107216081208.

The previous prime is 134020101463. The next prime is 134020101539. The reversal of 134020101515 is 515101020431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 515101020431 = 1373759861463.

It is a cyclic number.

It is not a de Polignac number, because 134020101515 - 26 = 134020101451 is a prime.

It is a super-2 number, since 2×1340201015152 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13402010147 + ... + 13402010156.

It is an arithmetic number, because the mean of its divisors is an integer number (40206030456).

Almost surely, 2134020101515 is an apocalyptic number.

134020101515 is a deficient number, since it is larger than the sum of its proper divisors (26804020309).

134020101515 is an equidigital number, since it uses as much as digits as its factorization.

134020101515 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26804020308.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 134020101515 its reverse (515101020431), we get a palindrome (649121121946).

The spelling of 134020101515 in words is "one hundred thirty-four billion, twenty million, one hundred one thousand, five hundred fifteen".

Divisors: 1 5 26804020303 134020101515