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134020332013 = 467557515227
BaseRepresentation
bin111110011010000111…
…0111111100111101101
3110210221002220021100111
41330310032333213231
54143433201111023
6141322412500021
712453102011641
oct1746416774755
9423832807314
10134020332013
1151923a90077
1221b8317a611
13c83aa94809
1466b53d2c21
153745ca300d
hex1f343bf9ed

134020332013 has 8 divisors (see below), whose sum is σ = 134548700832. Its totient is φ = 133492995696.

The previous prime is 134020331999. The next prime is 134020332041. The reversal of 134020332013 is 310233020431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134020332013 - 213 = 134020323821 is a prime.

It is a super-2 number, since 2×1340203320132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134020332113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2506 + ... + 517732.

It is an arithmetic number, because the mean of its divisors is an integer number (16818587604).

Almost surely, 2134020332013 is an apocalyptic number.

It is an amenable number.

134020332013 is a deficient number, since it is larger than the sum of its proper divisors (528368819).

134020332013 is an equidigital number, since it uses as much as digits as its factorization.

134020332013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 516251.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 134020332013 its reverse (310233020431), we get a palindrome (444253352444).

The spelling of 134020332013 in words is "one hundred thirty-four billion, twenty million, three hundred thirty-two thousand, thirteen".

Divisors: 1 467 557 260119 515227 240611009 286981439 134020332013