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134020332113 is a prime number
BaseRepresentation
bin111110011010000111…
…0111111101001010001
3110210221002220021111012
41330310032333221101
54143433201111423
6141322412500305
712453102012143
oct1746416775121
9423832807435
10134020332113
1151923a90158
1221b8317a695
13c83aa94885
1466b53d2c93
153745ca3078
hex1f343bfa51

134020332113 has 2 divisors, whose sum is σ = 134020332114. Its totient is φ = 134020332112.

The previous prime is 134020332107. The next prime is 134020332139. The reversal of 134020332113 is 311233020431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117918752449 + 16101579664 = 343393^2 + 126892^2 .

It is a cyclic number.

It is not a de Polignac number, because 134020332113 - 26 = 134020332049 is a prime.

It is a super-2 number, since 2×1340203321132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134020332913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010166056 + 67010166057.

It is an arithmetic number, because the mean of its divisors is an integer number (67010166057).

Almost surely, 2134020332113 is an apocalyptic number.

It is an amenable number.

134020332113 is a deficient number, since it is larger than the sum of its proper divisors (1).

134020332113 is an equidigital number, since it uses as much as digits as its factorization.

134020332113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 134020332113 its reverse (311233020431), we get a palindrome (445253352544).

The spelling of 134020332113 in words is "one hundred thirty-four billion, twenty million, three hundred thirty-two thousand, one hundred thirteen".