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134020521531233 is a prime number
BaseRepresentation
bin11110011110010000010101…
…100101000001011101100001
3122120112020101120120210022022
4132132100111211001131201
5120031243012002444413
61153012102211351225
740141443313642661
oct3636202545013541
9576466346523268
10134020521531233
1139780869550a67
12130460a95b2515
1359a2108b0b9bc
1425148b0b821a1
1510762abe8c608
hex79e415941761

134020521531233 has 2 divisors, whose sum is σ = 134020521531234. Its totient is φ = 134020521531232.

The previous prime is 134020521531131. The next prime is 134020521531251. The reversal of 134020521531233 is 332135125020431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101564632773184 + 32455888758049 = 10077928^2 + 5697007^2 .

It is a cyclic number.

It is not a de Polignac number, because 134020521531233 - 216 = 134020521465697 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134020521531193 and 134020521531202.

It is not a weakly prime, because it can be changed into another prime (134020521531263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010260765616 + 67010260765617.

It is an arithmetic number, because the mean of its divisors is an integer number (67010260765617).

Almost surely, 2134020521531233 is an apocalyptic number.

It is an amenable number.

134020521531233 is a deficient number, since it is larger than the sum of its proper divisors (1).

134020521531233 is an equidigital number, since it uses as much as digits as its factorization.

134020521531233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 134020521531233 its reverse (332135125020431), we get a palindrome (466155646551664).

The spelling of 134020521531233 in words is "one hundred thirty-four trillion, twenty billion, five hundred twenty-one million, five hundred thirty-one thousand, two hundred thirty-three".