Base | Representation |
---|---|
bin | 11000111101101010… |
… | …00011000000011010 |
3 | 1021121000110110022121 |
4 | 30132311003000122 |
5 | 204421420434224 |
6 | 10053514011454 |
7 | 653055114505 |
oct | 143665030032 |
9 | 37530413277 |
10 | 13402124314 |
11 | 57581713a7 |
12 | 2720416b8a |
13 | 13577a8197 |
14 | 911d2413c |
15 | 5368d4be4 |
hex | 31ed4301a |
13402124314 has 4 divisors (see below), whose sum is σ = 20103186474. Its totient is φ = 6701062156.
The previous prime is 13402124269. The next prime is 13402124327. The reversal of 13402124314 is 41342120431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13401998289 + 126025 = 115767^2 + 355^2 .
It is a super-2 number, since 2×134021243142 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350531077 + ... + 3350531080.
Almost surely, 213402124314 is an apocalyptic number.
13402124314 is a deficient number, since it is larger than the sum of its proper divisors (6701062160).
13402124314 is an equidigital number, since it uses as much as digits as its factorization.
13402124314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6701062159.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13402124314 its reverse (41342120431), we get a palindrome (54744244745).
The spelling of 13402124314 in words is "thirteen billion, four hundred two million, one hundred twenty-four thousand, three hundred fourteen".
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