Base | Representation |
---|---|
bin | 1100001100000111000101… |
… | …1001011000001000111001 |
3 | 1202110020102101120220101222 |
4 | 3003001301121120020321 |
5 | 3224040201303111101 |
6 | 44300515203521425 |
7 | 2552164010060432 |
oct | 303016131301071 |
9 | 52406371526358 |
10 | 13402200441401 |
11 | 42a7928833302 |
12 | 1605529989275 |
13 | 762a8c150c95 |
14 | 34495453c489 |
15 | 18394e33801b |
hex | c3071658239 |
13402200441401 has 2 divisors, whose sum is σ = 13402200441402. Its totient is φ = 13402200441400.
The previous prime is 13402200441397. The next prime is 13402200441449. The reversal of 13402200441401 is 10414400220431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11299413331600 + 2102787109801 = 3361460^2 + 1450099^2 .
It is an emirp because it is prime and its reverse (10414400220431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13402200441401 - 22 = 13402200441397 is a prime.
It is not a weakly prime, because it can be changed into another prime (13402200441451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701100220700 + 6701100220701.
It is an arithmetic number, because the mean of its divisors is an integer number (6701100220701).
Almost surely, 213402200441401 is an apocalyptic number.
It is an amenable number.
13402200441401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402200441401 is an equidigital number, since it uses as much as digits as its factorization.
13402200441401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 26.
Adding to 13402200441401 its reverse (10414400220431), we get a palindrome (23816600661832).
The spelling of 13402200441401 in words is "thirteen trillion, four hundred two billion, two hundred million, four hundred forty-one thousand, four hundred one".
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