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13402210421177 is a prime number
BaseRepresentation
bin1100001100000111000111…
…1111011100100110111001
31202110020110002100221002022
43003001301333130212321
53224040211331434202
644300520201444225
72552164160644124
oct303016177344671
952406402327068
1013402210421177
1142a793342a256
1216055311a0675
13762a91236586
143449559b93bb
15183950159ea2
hexc3071fdc9b9

13402210421177 has 2 divisors, whose sum is σ = 13402210421178. Its totient is φ = 13402210421176.

The previous prime is 13402210421077. The next prime is 13402210421239. The reversal of 13402210421177 is 77112401220431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11385367356841 + 2016843064336 = 3374221^2 + 1420156^2 .

It is a cyclic number.

It is not a de Polignac number, because 13402210421177 - 234 = 13385030551993 is a prime.

It is not a weakly prime, because it can be changed into another prime (13402210421077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701105210588 + 6701105210589.

It is an arithmetic number, because the mean of its divisors is an integer number (6701105210589).

Almost surely, 213402210421177 is an apocalyptic number.

It is an amenable number.

13402210421177 is a deficient number, since it is larger than the sum of its proper divisors (1).

13402210421177 is an equidigital number, since it uses as much as digits as its factorization.

13402210421177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18816, while the sum is 35.

The spelling of 13402210421177 in words is "thirteen trillion, four hundred two billion, two hundred ten million, four hundred twenty-one thousand, one hundred seventy-seven".