Base | Representation |
---|---|
bin | 1100001100000111011101… |
… | …1010100010110010111001 |
3 | 1202110020200102120122221211 |
4 | 3003001313122202302321 |
5 | 3224040403130113424 |
6 | 44300533212003121 |
7 | 2552166344230105 |
oct | 303016732426271 |
9 | 52406612518854 |
10 | 13402301410489 |
11 | 42a797a826932 |
12 | 16055577604a1 |
13 | 762aa70438c4 |
14 | 344963b02905 |
15 | 18395812eb94 |
hex | c30776a2cb9 |
13402301410489 has 2 divisors, whose sum is σ = 13402301410490. Its totient is φ = 13402301410488.
The previous prime is 13402301410429. The next prime is 13402301410499. The reversal of 13402301410489 is 98401410320431.
13402301410489 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13080916730025 + 321384680464 = 3616755^2 + 566908^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13402301410489 is a prime.
It is not a weakly prime, because it can be changed into another prime (13402301410429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701150705244 + 6701150705245.
It is an arithmetic number, because the mean of its divisors is an integer number (6701150705245).
Almost surely, 213402301410489 is an apocalyptic number.
It is an amenable number.
13402301410489 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402301410489 is an equidigital number, since it uses as much as digits as its factorization.
13402301410489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 40.
The spelling of 13402301410489 in words is "thirteen trillion, four hundred two billion, three hundred one million, four hundred ten thousand, four hundred eighty-nine".
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