Base | Representation |
---|---|
bin | 1100001100000111011101… |
… | …1110011011111110011111 |
3 | 1202110020200111111112000112 |
4 | 3003001313132123332133 |
5 | 3224040403410244020 |
6 | 44300533245520235 |
7 | 2552166356010542 |
oct | 303016736337637 |
9 | 52406614445015 |
10 | 13402302431135 |
11 | 42a7980363742 |
12 | 1605557b7307b |
13 | 762aa7310337 |
14 | 344963cca859 |
15 | 1839582822c5 |
hex | c307779bf9f |
13402302431135 has 8 divisors (see below), whose sum is σ = 16082815037616. Its totient is φ = 10721807198080.
The previous prime is 13402302431117. The next prime is 13402302431153. The reversal of 13402302431135 is 53113420320431.
It is an interprime number because it is at equal distance from previous prime (13402302431117) and next prime (13402302431153).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13402302431135 - 26 = 13402302431071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2581226 + ... + 5785095.
It is an arithmetic number, because the mean of its divisors is an integer number (2010351879702).
Almost surely, 213402302431135 is an apocalyptic number.
13402302431135 is a deficient number, since it is larger than the sum of its proper divisors (2680512606481).
13402302431135 is an equidigital number, since it uses as much as digits as its factorization.
13402302431135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8686713.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 13402302431135 its reverse (53113420320431), we get a palindrome (66515722751566).
The spelling of 13402302431135 in words is "thirteen trillion, four hundred two billion, three hundred two million, four hundred thirty-one thousand, one hundred thirty-five".
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