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134023304115 = 3255695234263
BaseRepresentation
bin111110011010001101…
…0010101001110110011
3110210221022111021022100
41330310122111032303
54143434431212430
6141323000311443
712453136200651
oct1746432251663
9423838437270
10134023304115
1151925730058
1221b84172583
13c83b59555c
1466b5967dd1
15374618d960
hex1f346953b3

134023304115 has 24 divisors (see below), whose sum is σ = 232715377440. Its totient is φ = 71353459584.

The previous prime is 134023304101. The next prime is 134023304123. The reversal of 134023304115 is 511403320431.

It is a happy number.

134023304115 is a `hidden beast` number, since 1 + 340 + 2 + 3 + 304 + 1 + 15 = 666.

It is not a de Polignac number, because 134023304115 - 25 = 134023304083 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2591527 + ... + 2642736.

It is an arithmetic number, because the mean of its divisors is an integer number (9696474060).

Almost surely, 2134023304115 is an apocalyptic number.

134023304115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

134023304115 is a deficient number, since it is larger than the sum of its proper divisors (98692073325).

134023304115 is a wasteful number, since it uses less digits than its factorization.

134023304115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5234843 (or 5234840 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 134023304115 its reverse (511403320431), we get a palindrome (645426624546).

The spelling of 134023304115 in words is "one hundred thirty-four billion, twenty-three million, three hundred four thousand, one hundred fifteen".

Divisors: 1 3 5 9 15 45 569 1707 2845 5121 8535 25605 5234263 15702789 26171315 47108367 78513945 235541835 2978295647 8934886941 14891478235 26804660823 44674434705 134023304115