Base | Representation |
---|---|
bin | 1100001100000111110111… |
… | …1101000011101000110001 |
3 | 1202110020222002000112202112 |
4 | 3003001331331003220301 |
5 | 3224041114221334301 |
6 | 44300552131255105 |
7 | 2552202145605314 |
oct | 303017575035061 |
9 | 52406862015675 |
10 | 13402411121201 |
11 | 42a7a26750143 |
12 | 160558844a495 |
13 | 762ac39a739b |
14 | 34497450097b |
15 | 183962aa19bb |
hex | c307df43a31 |
13402411121201 has 2 divisors, whose sum is σ = 13402411121202. Its totient is φ = 13402411121200.
The previous prime is 13402411121173. The next prime is 13402411121227. The reversal of 13402411121201 is 10212111420431.
13402411121201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10719861774400 + 2682549346801 = 3274120^2 + 1637849^2 .
It is a cyclic number.
It is not a de Polignac number, because 13402411121201 - 234 = 13385231252017 is a prime.
It is not a weakly prime, because it can be changed into another prime (13402411126201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701205560600 + 6701205560601.
It is an arithmetic number, because the mean of its divisors is an integer number (6701205560601).
Almost surely, 213402411121201 is an apocalyptic number.
It is an amenable number.
13402411121201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13402411121201 is an equidigital number, since it uses as much as digits as its factorization.
13402411121201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 13402411121201 its reverse (10212111420431), we get a palindrome (23614522541632).
The spelling of 13402411121201 in words is "thirteen trillion, four hundred two billion, four hundred eleven million, one hundred twenty-one thousand, two hundred one".
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