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13402444441 is a prime number
BaseRepresentation
bin11000111101101100…
…10001001010011001
31021121001001201110011
430132312101022121
5204422011210231
610053524521521
7653060620021
oct143666211231
937531051404
1013402444441
11575836a971
1227205502a1
13135788aac9
14911da8a81
155369499b1
hex31ed91299

13402444441 has 2 divisors, whose sum is σ = 13402444442. Its totient is φ = 13402444440.

The previous prime is 13402444403. The next prime is 13402444459. The reversal of 13402444441 is 14444420431.

13402444441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11814820416 + 1587624025 = 108696^2 + 39845^2 .

It is a cyclic number.

It is not a de Polignac number, because 13402444441 - 211 = 13402442393 is a prime.

It is not a weakly prime, because it can be changed into another prime (13402448441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701222220 + 6701222221.

It is an arithmetic number, because the mean of its divisors is an integer number (6701222221).

Almost surely, 213402444441 is an apocalyptic number.

It is an amenable number.

13402444441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13402444441 is an equidigital number, since it uses as much as digits as its factorization.

13402444441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24576, while the sum is 31.

Adding to 13402444441 its reverse (14444420431), we get a palindrome (27846864872).

The spelling of 13402444441 in words is "thirteen billion, four hundred two million, four hundred forty-four thousand, four hundred forty-one".