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13402516503 = 31092376021
BaseRepresentation
bin11000111101101101…
…00010110000010111
31021121001012101022010
430132312202300113
5204422021012003
610053530235303
7653061340065
oct143666426027
937531171263
1013402516503
11575840a022
122720585b33
1313578b484c
14911dc7035
15536961003
hex31eda2c17

13402516503 has 12 divisors (see below), whose sum is σ = 18035519208. Its totient is φ = 8853014880.

The previous prime is 13402516499. The next prime is 13402516511. The reversal of 13402516503 is 30561520431.

It is not a de Polignac number, because 13402516503 - 22 = 13402516499 is a prime.

It is a super-2 number, since 2×134025165032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402516583) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 152368 + ... + 223653.

It is an arithmetic number, because the mean of its divisors is an integer number (1502959934).

Almost surely, 213402516503 is an apocalyptic number.

13402516503 is a deficient number, since it is larger than the sum of its proper divisors (4633002705).

13402516503 is an equidigital number, since it uses as much as digits as its factorization.

13402516503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 376242 (or 376133 counting only the distinct ones).

The product of its (nonzero) digits is 10800, while the sum is 30.

The spelling of 13402516503 in words is "thirteen billion, four hundred two million, five hundred sixteen thousand, five hundred three".

Divisors: 1 3 109 327 11881 35643 376021 1128063 40986289 122958867 4467505501 13402516503