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1340254113 = 31140613761
BaseRepresentation
bin100111111100010…
…1010011110100001
310110101220222000020
41033320222132201
510221101112423
6340554144053
745132654252
oct11770523641
93411828006
101340254113
116285a1830
12314a22029
13184890393
14c9ddcb29
157c9e24e3
hex4fe2a7a1

1340254113 has 8 divisors (see below), whose sum is σ = 1949460576. Its totient is φ = 812275200.

The previous prime is 1340254079. The next prime is 1340254121. The reversal of 1340254113 is 3114520431.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1340254113 - 28 = 1340253857 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1340254133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20306848 + ... + 20306913.

It is an arithmetic number, because the mean of its divisors is an integer number (243682572).

Almost surely, 21340254113 is an apocalyptic number.

It is an amenable number.

1340254113 is a deficient number, since it is larger than the sum of its proper divisors (609206463).

1340254113 is a wasteful number, since it uses less digits than its factorization.

1340254113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40613775.

The product of its (nonzero) digits is 1440, while the sum is 24.

The square root of 1340254113 is about 36609.4811899868. The cubic root of 1340254113 is about 1102.5434568254.

Adding to 1340254113 its reverse (3114520431), we get a palindrome (4454774544).

The spelling of 1340254113 in words is "one billion, three hundred forty million, two hundred fifty-four thousand, one hundred thirteen".

Divisors: 1 3 11 33 40613761 121841283 446751371 1340254113