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134027497 is a prime number
BaseRepresentation
bin1111111110100…
…01100011101001
3100100012022011101
413333101203221
5233302334442
621144401401
73215133502
oct777214351
9310168141
10134027497
116972292a
1238a76261
13219c8a16
1413b2bba9
15bb76cb7
hex7fd18e9

134027497 has 2 divisors, whose sum is σ = 134027498. Its totient is φ = 134027496.

The previous prime is 134027471. The next prime is 134027521. The reversal of 134027497 is 794720431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133726096 + 301401 = 11564^2 + 549^2 .

It is an emirp because it is prime and its reverse (794720431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134027497 is a prime.

It is not a weakly prime, because it can be changed into another prime (134027897) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67013748 + 67013749.

It is an arithmetic number, because the mean of its divisors is an integer number (67013749).

Almost surely, 2134027497 is an apocalyptic number.

It is an amenable number.

134027497 is a deficient number, since it is larger than the sum of its proper divisors (1).

134027497 is an equidigital number, since it uses as much as digits as its factorization.

134027497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42336, while the sum is 37.

The square root of 134027497 is about 11577.0245313725. The cubic root of 134027497 is about 511.7579944047.

The spelling of 134027497 in words is "one hundred thirty-four million, twenty-seven thousand, four hundred ninety-seven".