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13403040419 is a prime number
BaseRepresentation
bin11000111101110001…
…00010101010100011
31021121002011222222102
430132320202222203
5204422134243134
610053545401015
7653065651406
oct143670425243
937532158872
1013403040419
11575873770a
12272079916b
131357a39162
149120c1d3d
15536a1637e
hex31ee22aa3

13403040419 has 2 divisors, whose sum is σ = 13403040420. Its totient is φ = 13403040418.

The previous prime is 13403040383. The next prime is 13403040451. The reversal of 13403040419 is 91404030431.

13403040419 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13403040419 is a prime.

It is a super-2 number, since 2×134030404192 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 13403040391 and 13403040400.

It is not a weakly prime, because it can be changed into another prime (13403040479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701520209 + 6701520210.

It is an arithmetic number, because the mean of its divisors is an integer number (6701520210).

Almost surely, 213403040419 is an apocalyptic number.

13403040419 is a deficient number, since it is larger than the sum of its proper divisors (1).

13403040419 is an equidigital number, since it uses as much as digits as its factorization.

13403040419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

The spelling of 13403040419 in words is "thirteen billion, four hundred three million, forty thousand, four hundred nineteen".